Eventum investigationis
Si vis, paginam "2T" crea! Conferantur etiam paginae 3 sequentes, in quibus quaesitum quodam modo continetur.
- computatur ita: A(t)=Arectangulum−A1=2t⋅at2−2a3⋅t3=2at3−2a3t3=4a3⋅t3{\displaystyle A(t)=A_{rectangulum}-A_{1}=2t\cdot at^{2}-{\frac {2a}{3}}\cdot t^{3}=2at^{3}-{\frac...5 chiliocteti (765 verba) - 17:37, 19 Ianuarii 2022
- ) ( t 2 + 1 ) 2 . {\displaystyle x={\frac {t^{2}-1}{t^{2}+1}},\ y={\frac {2t(t^{2}-1)}{(t^{2}+1)^{2}}}.} Lemniscus Booth, sive de Graeca Hippopede Procli...3 chiliocteti (246 verba) - 19:42, 24 Augusti 2020
- }\times n(1-t^{*})^{n-1}{\text{ ubi }}t^{*\prime }={\frac {2t}{\tau ^{2}}}} quo derivatur v = − x 0 ( − t ∗ ′ × 1 2 ( 1 − t ∗ ) − 1 /...41 chiliocteti (4 400 verba) - 14:33, 8 Februarii 2024
- haecque reducta abibit in istam, T(xdy−ydx)2t(A−∫Tdt)=dp1+pp{\displaystyle {\frac {T\left(xdy-ydx\right)}{2t\left(A-\int T\,dt\right)}}={\frac {dp}{1+pp}}}